3x^2-120x+200=0

Solution for 3x^2-120x+200=0 equation:

3x^2-120x+200=0

a = 3; b = -120; c = +200;
Δ = b2-4ac
Δ = -1202-4·3·200
Δ = 12000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12000}=\sqrt{400*30}=\sqrt{400}*\sqrt{30}=20\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-20\sqrt{30}}{2*3}=\frac{120-20\sqrt{30}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+20\sqrt{30}}{2*3}=\frac{120+20\sqrt{30}}{6}
$